Print a Pattern- #2

How to print this -

1
12
234
3456
45678









#include<stdio.h>
#include<conio.h>

int main()
{

int row,column,x;
for(row=1;row<=5;row++)
{
for(column=1;column<row+1;column++)
{
x=row+column-2;
if(x==0)
printf("1");
else
printf("%d",x);
}
printf("\n");
}
}


Code is 100% working.
Compiled with GCC 4.6.1 with -std=c99 option enabled.
IDE = orwell Dev-C++  v5.2.0.3

Print a Pattern - #1

How to print this -

Question-  Write a complete C program to print the following pattern for n number of rows, where n is supplied externally,

*       *

**     **

***   ***

**** ****

*********

#include<stdio.h>
#include<conio.h>

int main()
{
int n,star=0,space,width,i,j;

printf("ENTER LENGTH:  ");
scanf("%d",&n);
n+=1;
width=(n*2)-4;

for(i=0;i<n;i++)
{
space=width-star*2;

for(j=0;j<width+1;j++)
{
if(j<star||j>(star+space))
printf("*");
else
printf(" ");
}
printf("\n");
star++;
}
}

Code is 100% working.
Compiled with GCC 4.6.1 with -std=c99 option enabled.
IDE = orwell Dev-C++  v5.2.0.3